posted by cyrus .
find the equation of the line containing the points (2, -3) and has a slope perpendicular to the line 3x-5y+6=0
If two lines are perpendicular, then their slopes are the negative reciprocals of each other.
If the equation of one line is Ax + By + C = 0, then a perpendicular line would look like Bx - Ay + K = 0
So your new line would be 5x + 3y + K = 0
sub in the given point (2,-3), solve for K and you are done.
This is the easiest way to solve this type of question.