Posted by **cyrus** on Thursday, February 7, 2008 at 7:17am.

find the equation of the line containing the points (2, -3) and has a slope perpendicular to the line 3x-5y+6=0

- math -
**Reiny**, Thursday, February 7, 2008 at 7:23am
If two lines are perpendicular, then their slopes are the negative reciprocals of each other.

If the equation of one line is Ax + By + C = 0, then a perpendicular line would look like Bx - Ay + K = 0

So your new line would be 5x + 3y + K = 0

sub in the given point (2,-3), solve for K and you are done.

This is the easiest way to solve this type of question.

- math -
**aaron**, Thursday, February 7, 2008 at 4:29pm
whats 5+5

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