What mass of solution containing 6.50% sodium sulfate N2SO4 by mass contains 1.50g Na2SO4
Set up a proportion.
(g Na2SO4/g solution) = (1.50 g Na2SO4/x g solution).
Solve for x. Check my work.
how do you fine g solution
6.5 g Na2SO4 per 100 g solution.
6.5 goes on top, 100 goes on bottom.
so for this part
(g Na2SO4/g solution) = (1.50 g Na2SO4/x g solution).
it would be (g Na2SO4/ .065 g solution = 1.50 g Na2SO4/ x .065 g solution ) or did i miss place them
No.
It would be (6.5/100) = (1.50/x g solution)
Then cross multiply to obtain,
6.5*x = 100*1.5
x = ??
23.0769 right
The digits are right. I would round it to 23 since you have only two significant digits in the 6.5%. But 23 what? grams. mL. ounces. pounds.
To find the mass of the solution, you need to set up a proportion using the given information.
The proportion is:
(g Na2SO4/g solution) = (1.50 g Na2SO4/x g solution)
In this case, you are given the mass of sodium sulfate (Na2SO4) which is 1.50 g.
To solve for x, you cross-multiply and solve for x:
(g Na2SO4) * (x g solution) = (1.50 g Na2SO4) * (g solution)
Now, you can simplify the equation by dividing both sides by the grams of Na2SO4:
x g solution = (1.50 g Na2SO4) / (g Na2SO4)
Now, you need to use the given information that the solution contains 6.50% sodium sulfate by mass. This means that the solution can be expressed as:
6.50 g Na2SO4 / 100 g solution
Now you can substitute this value into the equation:
x g solution = (1.50 g Na2SO4) / (6.50 g Na2SO4 / 100 g solution)
To simplify, you can multiply both sides by 100:
100 * x g solution = (1.50 g Na2SO4) * (100 g solution / 6.50 g Na2SO4)
Now, you can cancel out the units of grams of Na2SO4:
100 * x g solution = (1.50 g) * (100 g solution) / (6.50)
Simplify the equation further:
100 * x g solution = 23.08 g solution
Finally, you can solve for x (the mass of the solution) by dividing both sides by 100:
x g solution = 23.08 g solution / 100
Now, you can calculate the mass of the solution:
x = 0.2308 g solution
Therefore, the mass of the solution containing 6.50% sodium sulfate by mass and 1.50 g of Na2SO4 is approximately 0.2308 g.