Homework Help: physical science

Posted by lisa on Wednesday, February 6, 2008 at 6:19pm.

a player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds.

how much force was exerted on the puck?

how much force did the puck exert on the hockey stick?

physical science - Damon, Wednesday, February 6, 2008 at 6:36pm
Force = rate of change of momentum (in other words m (delta v/ delta t) or m a)
F = m (change in velocity/change in time)
F = .2 (6/2) = .6 Newtons average during the 2 seconds.
Another way, which is really the same, is to say Force * time = impulse which is mass times change in velocity
F * 2 = .2 (6)
F = .6 Newtons again

Newton's third law says same force, .6 Newtons exerted back on the stick by the puck

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