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A saturated solution of ammonium sulfate, (NH4)2SO4, in water at 30 0C contains 78.0 g (NH4)2SO4 per 100.0 g H2O. What is the molality of this solution?

  • chemistry -

    Molality = #mols/kg solvent
    mols = g/molar mass

    mols (NH4)2SO4 = 78.0g x (1 mol/molar mass) = ??
    100.0 g H2O = 0.100 kg.
    Plug and chug.
    Post your work if you get stuck.

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