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August 4, 2015

Homework Help: Chem II

Posted by Ken on Tuesday, February 5, 2008 at 8:48pm.

What mass of PbI2 can be formed from 75.0 mL of 0.65 M NaI by adding excess Pb(NO3)2?
Pb(NO3)2 + 2NaI ---> PbI + 2NaNO3

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