Tuesday

September 30, 2014

September 30, 2014

Posted by **Gabby** on Tuesday, February 5, 2008 at 6:52pm.

Can you show the formula for how you found the answer and explain how to do it.

- Science calculations -
**drwls**, Tuesday, February 5, 2008 at 7:27pmThe velocity achieved after going a distance X while accelerating at a rate a, from a standing start, is

V = sqrt (2 a X)

Rearrange that equaiton to arrive at the acceleration "a" needed to achieve velocity V at runway distance X:

2aX = V^2

a = V^2/(2X)

- Science calculations -
**Gabby**, Tuesday, February 5, 2008 at 7:57pm2.52 m/s^2 is what I got...its a choice on the paper

Thanks

- Science calculations -

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