Posted by **help please** on Monday, February 4, 2008 at 11:47pm.

find the equation in slope-intercept form for the line that contains the given point and that is parallel to the given line.

M(-5,2); -3x+8y=24

- algebra -
**drwls**, Tuesday, February 5, 2008 at 1:03am
I have no idea what the M means in front of (-5,2), so will ignore it.

The slope of the given line can be seen by rewriting the equation in y = mx+b form:

y = (3/8)x + 3

The slope is therefore 3/8.

A line passing through (-5,2) with that slope can be written

y -2 = (3/8)[x -(-5)] = 3/8(x+5)

or

y = (3/8)x + 31/8

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