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Posted by **chelsea** on Monday, February 4, 2008 at 8:03pm.

14.log50+log(x/2)=2

23.log72-log(2x/3)=0

Could someone please explain to me how to solve these?

- algebra -
**joe neval**, Monday, February 4, 2008 at 8:10pm1

32

58

- algebra -
**chelsea**, Monday, February 4, 2008 at 8:12pmthanks, but how do i solve them?

- algebra -
**bobpursley**, Monday, February 4, 2008 at 8:18pmremember the rule of logs?

Log (ab)= loga + logb so, take 14 as an example:

log50 + log(x/2)=2

log(50x/2)=2

50x/2= antilog2

solve for x

On 23, the formula is

log(a/b)= loga - logb

- algebra -
**chelsea**, Monday, February 4, 2008 at 8:20pmthanks!

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