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December 19, 2014

December 19, 2014

Posted by **stew** on Monday, February 4, 2008 at 6:42pm.

- math -
**drwls**, Monday, February 4, 2008 at 6:56pmAssuming the log base is 10, then

antilog (-0.05) = 10^.05 = 1/10^.05 = 1.1,2202 = 0.89125

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