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August 30, 2014

August 30, 2014

Posted by **Skye** on Monday, February 4, 2008 at 6:40pm.

x^2y+y^2x

P.S: It's calculus

- Math -
**drwls**, Monday, February 4, 2008 at 6:53pmDifferentiate with respect to y, recognizing that x is a function of y.

You cannot "find" dx/dy unless you write an equation. You have only written a formula for a function g(x,y).

If x^2*y + y^2*x = C (any constant), then

x^2 + y*2x*dx/dy + 2yx + y^2 dx/dy = 0

dx/dy(y^2x + y^2) = -x^2 -2yx

dx/dy = -x(x-2y)/[y^2(1+x)]

- Math -
**Damon**, Monday, February 4, 2008 at 6:54pmI think you want this equal to a constant if you want a solutionyou want dx/dy so differentiate wrt y

x^2 + y 2 x dx/dy+ y^2 dx/dy + x 2 y

= x^2 + 2 xy dx/dy + y^2 dx/dy + 2 x y

= dx/dy (2xy + y^2) + x^2 + 2xy

now if the right hand were a constant, then that = 0 so

dx/dy = -(x^2+2xy)/(y^2+2xy)

- Math -
**Anonymous**, Wednesday, February 6, 2008 at 4:07amy = x^2y+y^2x

dy/dx = 2y X^2y-1 + 2x Y^2x-1

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