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April 16, 2014

April 16, 2014

Posted by **J** on Monday, February 4, 2008 at 5:59pm.

Once again, I am lost!!!

- Physics -
**Damon**, Monday, February 4, 2008 at 6:38pma) C = q/V so q = C V

= 5*10^-6 * 1.5

= 7.5 * 10^-6 Coulombs

now do E = (1/2) C (1.5)^2 to get energy

E = .5 (5*10^-6)(2.25)

E = 5.63*10^-6 Joules

b) Luckily we derived this in your last question, but now that I see your questions you probably have it in your book and have not had calculus so

E = (1/2) C V^2 from your book or the other problem

E = (1/2) C (q/C)^2

(q/C)^2 = 2 E/C

q^2/C^2 = 2 E/C

q^2 = 2 E C

q = sqrt (2E*C)

q = sqrt (2 * 5 * 10*-6)

q = 10^-3 sqrt (10)

q = 3.16 * 10^-3 coulombs

c)V = q/C = 2.24*10^-3 / 5*10^-6

V = .447* 10^3 = 447 volts, watch out

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