Posted by **Anonymous** on Monday, February 4, 2008 at 5:51pm.

2^2x-1 - 3 times 2^x-1 + 1 = 0

- Algebra -
**Damon**, Monday, February 4, 2008 at 6:05pm
if either term is 0, the whole thing is zero, so this is two problems:

a) 2^(2x-1) - 3 = 0

or

b) 2^(x-1) + 1 = 0

NOTE - You did not give me parentheses, so I am guessing what you mean.

problem a

2^(2x-1) = 3

(2x-1) log 2 = log 3

(2x-1) = .477/.301 = 1.58

2x = 2.58

x = 1.29

or

problem b

2^(x-1) = -1

there is no such thing as log -1. I am stuck, no solution

the question is: Two to what power = -1

There is no such power.

therefore the only solution is problem a

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