February 19, 2017

Homework Help: Algebra 2

Posted by Amanda on Monday, February 4, 2008 at 4:58pm.

Approximate to the nearest tenth the positive real zeroes of f(x)=x^2+1. I got .6

Solve over the set of complex numbers.
x^4-13x^2+36=0 i got -3,-2,2,3 but i don't know if i even did it right.

Solve x^2+4x9=0 by completing the square. I don't even know where to begin on this one. So help me please!!!!! I have a test on this stuff Wed.

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