Posted by melissa on Monday, February 4, 2008 at 1:28pm.
Whether the collision is elastic or inelastic, the total momentum of the two balls in the direction perpendicular to the cue ball's initial direction must be zero, since there was no original momentum in that direction. Therefore
MV1 sin 37 - MV2 sin A = 0
In addition,
M Vo = M cos 37 + M V2 cos A
since momentum in the forward direction is conserved.
The M's all cancel out
Vo = 0.75 m/s
V1 = 0.25 m/s is the eight-ball's final velocity.
"A" is the unknown angle of the cue ball, and V2 is its velocity. It will be a negative angle.
You have two equations in two unknowns to solve.
We will be glad to critique your work.
The velocity is 0.0000 m/s
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