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March 2, 2015

March 2, 2015

Posted by **Jen** on Monday, February 4, 2008 at 10:58am.

A naturalist leads whale watch trips every morning in March. Teh number of whales seen ha a Poisson distributyion with a mena of 2.2. Find the probability that on a randomly selected trip, the number of whales seen is 5.

- Statistics -
**SraJMcGin**, Monday, February 4, 2008 at 12:43pmThank you for using the Jiskha Homework Help Forum. This i s not my area, but here are some sites on Poisson Distribution:

1. http://en.wikipedia.org/wiki/Poisson_distribution

2. (part II of #1): http://en.wikipedia.org/wiki/Poisson_process

3. http://mathworld.wolfram.com/PoissonDistribution.html

4. http://hyperphysics.phy-astr.gsu.edu/Hbase/math/poifcn.html

5. http://www.itl.nist.gov/div898/handbook/eda/section3/eda366j.htm

6. (queing, etc.): http://home.ched.coventry.ac.uk/Volume/Vol4/listof.htm

- Statistics -
**Jen-Can anyone else help me?**, Monday, February 4, 2008 at 3:16pmHelp

- Statistics -
**economyst**, Monday, February 4, 2008 at 4:19pmJen:

If you went to the wikipedia site suggested by SraJMcGin, you would have the formula for calculating probabilities following a poisson distribution.

The Poisson distrbution is

f(k,a) =(a^k)*(e^-a)/k! where a is the expected observed in a time period, and k is the actual observed, and e is the exponential e. (Go to the wikipedia site; they can express formulas much better than here on Jiskha.)

In your example a=2.2, and k=5. Plug these into your formula. Hint: I get about 4.8%

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