Posted by nat on Monday, February 4, 2008 at 2:33am.
Two capacitors, C1=25.0x10^6 and C2=5.0x10^6 are connected in parallel and charged with a 100V power supply.
a)calculate the total energy stored in the 2 capacitors
b) what potential difference would be required across the same 2 capacitors connected in series in order that the combination store the same energy as in a)?
ENERGY STORED=1/2C*DELTA V^2
1/2(25.0e^6 + 5.0e^6)(100)^2
=0.15KJ OR 150J, IS THIS RIGHT? IF NOT HOW DO I GET THE RIGHT ANSWER?
B)1/Ceq= 1/25.0e^6 + 1/5.0e^6= 4.16e^6
DELTA V= SQRT 2x (ENERGY STORED=150J)/
4.16e^6 = 8492v?????? CAN SOMEONE TELL ME IF IM DOING THIS RIGHT?

PHYSICS  drwls, Monday, February 4, 2008 at 2:47am
The stored energy that you calculate with that formula is in J, not kJ. The answer to the first part is 0.15 J
For the second part, require that
(1/2)Ceq*V^2 = 0.15 J, and solve for V. You are correct that Ceq = 4.167*10^6 F

PHYSICS  drwls, Monday, February 4, 2008 at 6:59am
Yes

PHYSICS  Anonymous, Saturday, February 27, 2016 at 4:56am
yes
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