Posted by **nat** on Monday, February 4, 2008 at 2:33am.

Two capacitors, C1=25.0x10^-6 and C2=5.0x10^-6 are connected in parallel and charged with a 100-V power supply.

a)calculate the total energy stored in the 2 capacitors

b) what potential difference would be required across the same 2 capacitors connected in series in order that the combination store the same energy as in a)?

ENERGY STORED=1/2C*DELTA V^2

1/2(25.0e^-6 + 5.0e^-6)(100)^2

=0.15KJ OR 150J, IS THIS RIGHT? IF NOT HOW DO I GET THE RIGHT ANSWER?

B)1/Ceq= 1/25.0e^-6 + 1/5.0e^-6= 4.16e^-6

DELTA V= SQRT 2x (ENERGY STORED=150J)/

4.16e^-6 = 8492v?????? CAN SOMEONE TELL ME IF IM DOING THIS RIGHT?

- PHYSICS -
**drwls**, Monday, February 4, 2008 at 2:47am
The stored energy that you calculate with that formula is in J, not kJ. The answer to the first part is 0.15 J

For the second part, require that

(1/2)Ceq*V^2 = 0.15 J, and solve for V. You are correct that Ceq = 4.167*10^-6 F

- PHYSICS -
**drwls**, Monday, February 4, 2008 at 6:59am
Yes

- PHYSICS -
**Anonymous**, Saturday, February 27, 2016 at 4:56am
yes

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