Sunday

May 1, 2016
Posted by **devon** on Sunday, February 3, 2008 at 7:49pm.

(x - 3)(x – 4)/(x – 5)(x – 6)^2 >or= 0

any help?

- math -
**Damon**, Sunday, February 3, 2008 at 9:01pmundefined for x = 5 or x = 6

(x-6)^2 always + where defined

function is zero at x = 3, x = 4

NOW sketch a graph

for x between 3 and 4. the denominator is - and the numerator is -, so >/= 0

between

x = 3 and x = 4

for x less than 3, denominator still - and numerator + so less than 0, not here

for x between 4 and 5, denominator is - and numerator is + so less than 0, not here

for x between 5 and 6, denominator is + and numerator is +, so yes

for x > 6, both numerator and denominator are + so yes