Monday
March 27, 2017

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Solve
(x - 3)(x – 4)/(x – 5)(x – 6)^2 >or= 0


any help?

  • math - ,

    undefined for x = 5 or x = 6
    (x-6)^2 always + where defined
    function is zero at x = 3, x = 4
    NOW sketch a graph

    for x between 3 and 4. the denominator is - and the numerator is -, so >/= 0
    between
    x = 3 and x = 4

    for x less than 3, denominator still - and numerator + so less than 0, not here

    for x between 4 and 5, denominator is - and numerator is + so less than 0, not here

    for x between 5 and 6, denominator is + and numerator is +, so yes

    for x > 6, both numerator and denominator are + so yes

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