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February 28, 2015

February 28, 2015

Posted by **Michael** on Sunday, February 3, 2008 at 3:39pm.

- Physics -
**Damon**, Sunday, February 3, 2008 at 4:18pmThere is no change of momentum of anything in the original, call it x, direction. Both the rocket and the expelled gas will continue to move at 2000 m/s

In the y direction. the gas moves in the + y direction and the rocket moves in the - y direction. However the total y momentum of the system remains zero since there was no net force on the system.

If the mass of gas is m, the remaining mass of the rocket is (2000-m)

the y direction speed of the remaining rocket is -2000 tan (18) = -650 m/s

The y momentum of the gas is m (+500)

The y momentum of the remaining rocket is (2000-m)(-650)

so

500 m -650(2000-m) = 0

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