Saturday

September 20, 2014

September 20, 2014

Posted by **Marysvoice** on Sunday, February 3, 2008 at 2:24pm.

sqrt18a^7b times sqrt27a^8b^6

Jake 1214-

18 = 9 * 2 then sqrt 18 = 3sqrt2

sqrt a^7 = a^3 * sqrt a

27 = 9 * 3 then sqrt 27 = 3 sqrt3

sqrt a^8 = a^4

sqrt b^6 = b^3

Now just multiply the like-terms together.

3sqrt6 and sqrt2a^4?

- Algebra -
**Jake1214**, Sunday, February 3, 2008 at 2:48pm.. 3sqrt6 and sqrt2a^4?

So you simplified the problem first as I said above and you get:

3(a^3)sqrt(2a) * 3(a^4)(b^3)sqrt(3)

and then you multiply those 2 things together and you get:

9(a^7)(b^3)sqrt(6a)

**Answer this Question**

**Related Questions**

Math - How do you find a square root of a number that's not a perfect square? I'...

Math Help please!! - Could someone show me how to solve these problems step by ...

math,algebra,help - Directions are simplify by combining like terms. x radiacal ...

Algebra - multiplying sq rts sqrt18a^7b times sqrt27a^8b^6 I think I need to ...

Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...

Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...

Algebra - Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r ...

Inequality - When I solve the inquality 2x^2 - 6 < 0, I get x < + or - ...

math calculus please help! - l = lim as x approaches 0 of x/(the square root of...

Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...