Posted by Lucy on Sunday, February 3, 2008 at 11:43am.
The problem is 5x to the 3rd times (7x)squared.
I multiplied (7x)(7x) first and got x squared + 14x + 49. Then I multiplied each of those by 5x to the 3rd and came up with an answer of: 5x to the 5th + 70x to the 4th + 245x to the 3rd. Did I get this one correct??

Algebra II  drwls, Sunday, February 3, 2008 at 12:58pm
<<I multiplied (7x)(7x) first and got x squared + 14x + 49.>>
Well you did that wrong, as well as some other steps.
(7x)^2 = 49x^2
The polynomial you wrote is (x+7)^2
5x^3*(7x)^2 = 5*49 x^5 = 245 x^5