Wednesday

October 1, 2014

October 1, 2014

Posted by **alan** on Saturday, February 2, 2008 at 1:38pm.

1) What is the pH of a 0.05 M solution of TRIS acid (pka = 8.3)?

My answer: I used the formula pH= (pka- log (HA)} /2 then I plugged in:

pH= 8.3-log(0.050)/2

pH= 4.8

2) What is the pH of a 0.045 M solution of TRIS base?

My answer: I used the formula PH=pka+14+log (base)/2

Then i plugged in:

pH=8.3+14+log(0.045M)/2 =

pH=10

3) How many total mL of 1 M NaOH can you add to the solution in problem 1 and still have a good buffer (that is, within 1 pH unit of the pka)?

Thank you.

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