what is the mass in grams of one molecule of ethanoic acid CH3COOH?
[(12 + (3x1) + 12 + (2x16) + 1)]/6.02*10^23 = ? grams
Add up the atomic mass numbers of all atoms in the molecule. Then divide by Avogadro's number
To calculate the mass of one molecule of ethanoic acid (CH3COOH) in grams, we need to determine the atomic masses of the elements and add them up.
The atomic masses of carbon (C), hydrogen (H), and oxygen (O) are:
- Carbon (C) atomic mass = 12.01 g/mol
- Hydrogen (H) atomic mass = 1.008 g/mol
- Oxygen (O) atomic mass = 16.00 g/mol
Now let's calculate the mass of one molecule of ethanoic acid (CH3COOH):
1 carbon atom (C) = 12.01 g/mol
2 hydrogen atoms (H) = 2 * 1.008 g/mol
2 oxygen atoms (O) = 2 * 16.00 g/mol
Adding these values together:
Mass of carbon = 12.01 g/mol
Mass of hydrogen = 2 * 1.008 g/mol = 2.016 g/mol
Mass of oxygen = 2 * 16.00 g/mol = 32.00 g/mol
Total mass of ethanoic acid (CH3COOH):
12.01 g/mol + 2.016 g/mol + 32.00 g/mol = 46.03 g/mol
Therefore, the mass of one molecule (or 1 mole) of ethanoic acid (CH3COOH) is approximately 46.03 grams.
To determine the mass of one molecule of ethanoic acid (CH3COOH) in grams, we need to know the molar mass of ethanoic acid and then convert it to grams using Avogadro's number.
The molar mass of an element or compound is the mass of one mole of that substance and is expressed in grams/mole. To calculate the molar mass of ethanoic acid, we sum up the atomic masses of its constituent elements:
C (carbon) = 12.01 g/mol
H (hydrogen) = 1.008 g/mol
O (oxygen) = 16.00 g/mol
Now, let's calculate the molar mass of ethanoic acid (CH3COOH):
Molar mass = (2 * C) + (4 * H) + (2 * O) + H = (2 * 12.01) + (4 * 1.008) + (2 * 16.00) + 1.008 = 60.05 g/mol
Therefore, the molar mass of ethanoic acid is 60.05 g/mol.
Since one mole of any substance contains 6.022 x 10^23 particles (Avogadro's number), to find the mass of one molecule of ethanoic acid, we divide the molar mass by Avogadro's number:
Mass of one molecule = Molar mass / Avogadro's number
Mass of one molecule = 60.05 g/mol / (6.022 x 10^23 particles/mol)
Calculating this, we find the mass of one molecule of ethanoic acid to be approximately 9.98 x 10^-23 grams.