Calculate the force of gravity between a 2.50 kg newborn baby and a 80.0 kg doctor standing 0.250 m away. G = 6.67 E -11 N*m2/kg2

My work

Fg = (Gm1 Gm2) /d^2
m1=2.50 kg
m2=80.0 kg
d=0.250 m
g=6.67 E -11 N*m2/kg2

Fg = (Gm1 Gm2) /d^2
Fg= g ( 2.50 kg)(80.0 kg)/0.250m^2
Fg= (6.67 E -11 N*m2/kg2)( 2.50 kg)(80.0 kg)/0.250m^2
Fg=

I keep messing up at the end i cant get the right answer. I just needto know how to multiply that last part, im getting confused with the gravity part of it...

You have all the numbers correct in the formula, so all you have to do is make the calculation. Having 0.250^2 (which is 1/16) in the denominator is the same as multiplying by 16.

I get 2.13*10^-7 Newtons for the answer. All of the other dimensions cancel (kg and m) out

To multiply the last part, you need to multiply the gravitational constant (G), baby's mass (m1), and the doctor's mass (m2), and then divide it by the square of the distance between them (d^2).

So, the calculation would be:

Fg = (6.67 E -11 N*m2/kg2) * (2.50 kg) * (80.0 kg) / (0.250 m^2)

First, multiply the masses:

Fg = (6.67 E -11 N*m2/kg2) * (2.50 kg) * (80.0 kg)

Fg = 1.334 E -8 N * kg * m2 / kg2

Next, divide by the square of the distance:

Fg = (1.334 E -8 N * kg * m2 / kg2) / (0.250 m^2)

To divide by a square, you can simply multiply by the reciprocal of the square:

Fg = (1.334 E -8 N * kg * m2 / kg2) * (1 / (0.250 m^2))

Fg = 5.336 E -8 N

So, the force of gravity between the newborn baby and the doctor is 5.336 E -8 Newtons.

To calculate the force of gravity between the newborn baby and the doctor, you're on the right track using the formula:

Fg = (G * m1 * m2) / d^2

Where Fg is the force of gravity, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 is the mass of the newborn baby (2.50 kg), m2 is the mass of the doctor (80.0 kg), and d is the distance between them (0.250 m).

Let's plug in the values:

Fg = (6.67 x 10^-11 N*m^2/kg^2) * (2.50 kg) * (80.0 kg) / (0.250 m)^2

First, calculate the value inside the parentheses:

Fg = (6.67 x 10^-11 N*m^2/kg^2) * (200 kg^2) / (0.250 m)^2

Next, square the distance:

Fg = (6.67 x 10^-11 N*m^2/kg^2) * (200 kg^2) / (0.0625 m^2)

Now, let's multiply the numerical values:

Fg = (6.67 x 10^-11) * (200) / (0.0625)

Fg = 1.336 x 10^-8 N

So, the force of gravity between the newborn baby and the doctor is approximately 1.336 x 10^-8 N.

I had the advantage of using a hand calculator with scientific notation. I'm lazy.