If you have a 12.01g sample carbon. What would be the average mass of a carbon atoms if it is 1.994 x 10 to the 23 power g. How many carbon atoms are in the sample?
Numberatoms=masssample/massoneatom
Your question is unclear. The mass cannot be both 12.01 g and 1.994*10^23 g.
A 12.01 g sample of C is one mole, and therefore contains Avogadro's nunber of atoms, which is 6.02*10^23 atoms
The average mass of a C atom is
(12.01 g)/(6.02*10^23 atoms)
They all have the same mass, except for about 1% that are Carbon-13 isotope)
To find the average mass of a carbon atom, we can divide the total mass of the sample (12.01 g) by the total number of carbon atoms in the sample.
Given that the mass of a carbon atom is 1.994 x 10^(-23) g, we can set up the following equation:
Average mass of a carbon atom = Total mass of the sample / Total number of carbon atoms
To find the total number of carbon atoms, we need to divide the total mass of the sample by the mass of a single carbon atom:
Total number of carbon atoms = Total mass of the sample / Mass of a single carbon atom
Let's solve this:
1. Average mass of a carbon atom = 12.01 g / (1.994 x 10^(-23) g) ≈ 6.024 x 10^22 g.
Therefore, the average mass of a carbon atom in the sample is approximately 6.024 x 10^22 g.
2. To find the number of carbon atoms in the sample, we can divide the total mass of the sample by the average mass of a carbon atom:
Number of carbon atoms = Total mass of the sample / Average mass of a carbon atom
Number of carbon atoms = 12.01 g / (6.024 x 10^22 g) ≈ 1.992 x 10^(-21).
Thus, there are approximately 1.992 x 10^(-21) carbon atoms in the sample.