The average power dissipated in a stereo speaker is 56 W. Assuming that the speaker can be treated as a 4.0- resistance, find the peak value of the ac voltage applied to the speaker.

Already answered. Try to understand what I wrote before. You still are writing - for ohms, apparenbtly

Except for the change from 56 to 54 W, refer to

http://www.jiskha.com/display.cgi?id=1201749991

If the current is composed of Na+ ions (q = +e), how many such ions flow in 0.7 s?

To find the peak value of the AC voltage applied to the speaker, we can use the formula

P = (V^2) / R

where P is the power dissipated, V is the voltage, and R is the resistance.

Given that the average power dissipated is 56 W and the resistance is 4.0 Ω, we can rearrange the formula to solve for V:

V^2 = P * R
V^2 = 56 W * 4.0 Ω
V^2 = 224 V*Ω
V = sqrt(224 V*Ω)

Calculating this, we find that the peak value of the AC voltage applied to the speaker is approximately 14.97 V.