can someone check and see if i did this right
An 800 g solution of acid and water contains 128 g of acid. What percent of the solution is acid?
100=128/800*100
128/800=6.25
6.25*100=625
Your first two equations are both wrong.
128/800 = 0.16 = 16%
I'd set it up with %/100=part/whole, then multiply top to bottom across the equal sign and divide by the other number.
x/100=128/800
x=12800/800
x=16
Your 625 answer doesn't make sense, due to the fact that they want the percentage... if it doesn't make sense, it can't be right:)
<BSV=<ABS
X=34
Angle y is the sum of <asw and <wsc.
<ASW=180-UAS
=180-93
=87
To find the percentage of acid in the solution, you can use the formula:
Percentage of Acid = (Mass of Acid / Total Mass of Solution) * 100
In this case, the mass of the acid is given as 128 g and the total mass of the solution is 800 g.
Thus, the calculation would be:
Percentage of Acid = (128 g / 800 g) * 100
To check if your solution is correct, let's perform the calculation:
Percentage of Acid = (0.16) * 100
Percentage of Acid = 16%
Therefore, the percentage of acid in the solution is 16%.