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October 25, 2014

Homework Help: Calculus

Posted by Anonymous on Thursday, January 31, 2008 at 12:19am.

L'Hospital's Rule

Lim(lnx)^(x-1)
x->1+

This is what I did so far...
Form: 0^0
ln(lnx)/ (1/x-1)

-----------------------------------

I am not sure if you could use L'Hospital Rule (as stated in the instruction)for the 2 problems below:

lim [ln(y^2+2y)]/[lny]=1
y->0+

lim xlnx = 0
x->0+

I was able to solve them without using the Rule.

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