Sunday

December 21, 2014

December 21, 2014

Posted by **anonymous** on Wednesday, January 30, 2008 at 9:58pm.

- CALC -
**drwls**, Wednesday, January 30, 2008 at 11:17pmThat is a slowly varying function over that interval. It increases from 1.3438 at x=3 to 1.6151 at x = 5. An approximate value for the integral is the mean value times 2, or 2.96.

I suggest you review and apply Simpson's Rule for numerical integration and use it with ten intervals (h = 0.2). There is a description of the method and a formula for its accuracy at

http://mathworld.wolfram.com/SimpsonsRule.html

If you get about the same value with four intervals as you get with ten, you can be quite sure the error will be comparable to the difference betrween the two calculations.

Using Simpson's Rule with four intervals, I get 2.9378 for the integral.

**Answer this Question**

**Related Questions**

Python programming - A standard problem in mathematics is to measure the area ...

CALC - area under a curve - You have an unknown function that is monotone ...

math-calc - for x (-12, 10) the function f is defined: f(x)=x^7(x+2)^2 On which ...

Precalculus - f(x)=x^2-1 Graph the function. Estimate the intervals on which ...

math-calc - Consider the function f(x)= (2x+8)/(6x+3). For this function there ...

math - . Given the following function, f(x)=-x^2 -8x find: (a) vertex, (b) axis...

Math: Need Answer to study for a quizz. Help ASAP - Estimate the area under the...

Calc. - Find the area of the region bounded by the parabola y=x^2, the tangent ...

pre calc - The Identity Function The Squaring Function The Cubing Function The ...

algebra - Given the following function, find: (a) vertex (b) axis of symmetry (c...