Find two consecutive integers such that the sum of 3 times the first integer and 7 times second integer is 97.

call them n and n+1

3 n + 7 (n+1) = 97

you can do it now

To solve this problem, let's assume the first integer is represented by x.

The second integer will then be represented by x + 1 since it is the next consecutive integer.

According to the given information, we can set up the equation:

3x + 7(x + 1) = 97

Now, let's solve for x:

3x + 7x + 7 = 97
10x + 7 = 97
10x = 97 - 7
10x = 90
x = 90 / 10
x = 9

Hence, the first integer is 9, and the second integer is 9 + 1 = 10.