Tuesday

September 2, 2014

September 2, 2014

Posted by **an** on Wednesday, January 30, 2008 at 7:04pm.

- calculus -
**Count Iblis**, Wednesday, January 30, 2008 at 7:18pmdy/dx= (1+lnx)y --->

dy/y = (1 + ln(x)) dx --->

ln(y) = x ln(x) + c

Boundary condition:

y=1 when x=1 ---> c = 0

y = exp(x ln(x)) = x^x

**Answer this Question**

**Related Questions**

Calculus 1 - Find the derivative of y with respect to x. y=(x^6/6)(lnx)-(x^6/36...

calculus - sorry to ask a second question so soon, but i'm just not getting this...

Calculus - Find the derivatives, dy/dx for the following functions. a. x^2y^4 = ...

L'Hopital's rule - Find lim x->1+ of [(1/(x-1))-(1/lnx)]. Here is my work...

calculus - (a) find the intervals on which f is incrs or decrs. (b) find the ...

Calculus - Find the derivative of y with respect to x. y= [(x^5)/5]lnx-[(x^5)/25...

calculus - find dy/dx 1. y=(lnx)^3 2. y=x^4lnx 3. y=sin^3(lnx)

Calculus (improper integrals) - the integral from 0 to lnx of lnx/(x^1/2) thanks...

calculus - 1. e^ln3 - 2lnx 2. 2(lnx)^2 + lnx - 1 =0 3. d/dx (e^x . e^e^x)

calc - integral of 1 to e^4 dx/x(1+lnx) 1+lnx = a => dx/x = da dx/ x(1+lnx...