When a hot object is placed in contact with a cooler object, the hot object warms the cooler one. Can you say it loses as much temperature as the cooler one gains? Defend your answer.

It loses the same amount of heat. Now temperature change depends on the thermal capacity, the one with the greater thermal capacity will lose less temperature.

Heat= thermal capacity*deltatemp

When a hot object is placed in contact with a cooler object, heat transfer occurs. The heat flows from the hotter object to the cooler object until thermal equilibrium is reached, where both objects have the same temperature. However, it is not accurate to say that the hot object loses as much temperature as the cooler object gains.

To understand why, we need to consider the concept of specific heat capacity. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance by a certain amount. Different materials have different specific heat capacities. Therefore, it is important to note that the temperature change of an object depends not only on the amount of heat transferred but also on its specific heat capacity.

Here's an example to illustrate this concept: let's say we have a hot object with a high specific heat capacity, and a cooler object with a low specific heat capacity. When they come into contact, heat will flow from the hotter object to the cooler object. However, due to the difference in their specific heat capacities, the temperature change will not be equal. The hot object may lose some temperature, but it won't lose as much as the cooler object gains. This difference is because the hot object requires more heat energy to experience the same temperature change compared to the cooler object.

It is important to remember that temperature change is determined by several factors, including the specific heat capacities of the objects involved, the amount of heat transferred, and the thermal conductivity of the materials. So, while heat will be transferred from the hot object to the cooler one, it does not mean that the hot object loses as much temperature as the cooler object gains.