Posted by **Andrea** on Wednesday, January 30, 2008 at 6:14pm.

A mass m=.5kg on a spring with a spring constant. It is displaced by the distance x_max =20cm (.2m) from equilibrium on a frictionless horizontal surface. At the time t=0s the mass is released and it begins to oscillate. Assume that T=3.14s.

Find the following for when t=0, T/4, T/2, 3T/4, and T:

displacement

speed

restoring force (F=kx)

acceleration (a=F/m)

kinetic energy (1/2mv^2)

potential energy (1/2kx^2)

For t=0s I got: .2m, 0m/s, .4N, .8m/s^2, 0J, and .04J respectively. I got this first by finding the spring constant using this equation: T= 2*pi*(sqrt(m/k)) Thus k= roughly 2

Is this correct? Then I have trouble figuring out the rest because t= T/4 confuses me and I can't find the displacement at this particular time.

## Answer this Question

## Related Questions

- Physics Urgent please help - Consider an ideal spring that has an unstretched ...
- physics - Consider an ideal spring that has an unstretched length l0 = 3.9 m. ...
- Physics - Consider an ideal spring that has an unstretched length l0 = 3.9 m. ...
- physics - Consider an ideal spring that has an unstretched length l0 = 3.9 m. ...
- Physics - Consider an ideal spring that has an unstretched length l0 = 3.3 m. ...
- physics - A block with a mass of 0.5kg is pushed against a horizontal spring of ...
- Physics - A spring is mounted horizontally. A crate which has a mass of 8.5kg is...
- physics - A 96.3 g mass is attached to a horizontal spring with a spring ...
- physics - A 95.5 g mass is attached to a horizontal spring with a spring ...
- Physics (please help!!!!) - The mass m = 14 kg shown in the figure is displaced ...

More Related Questions