February 21, 2017

Homework Help: CHEMISTRY

Posted by Jake on Wednesday, January 30, 2008 at 6:05pm.

I'm in the same class as Catie, and we're working on the same lab; however, i chose a different approach.

here's what i have below, your help is much appreciated.

so i have X= g AgNO3
0.953-x = Ba(NO3)2
therefore .953-X-NO3=?

so far I caluclated the % of Ag and Ba in their nitrate salts:

% Ag in Ag2NO3= 107.87/161.91
= .666X

% Ba in Ba(NO3)2 = 137.33/261.32
= .526(.953-X)

i got this far, but now i'm stuck.

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