Homework Help: Physics

Posted by J on Wednesday, January 30, 2008 at 4:57pm.

A paralle plate air capacitor has a capacitance of 500.0 pF and a charge of magnitude 0.200 uC on each plate. The plates are 0.6 mm apart. (a) What is the potenetial difference between the plates? (b) What is the area of each plate? (c) What is the electric field magnitude between the plates? (d) What is the surface charge density on each plate?

ok..I am TOTALLY lost! someone help please! at least get me started! haha

Physics - drwls, Wednesday, January 30, 2008 at 6:02pm
a) Q = CV so V = Q/C
You don't need to now the plate spacing yet, but you will fr the next step

b) C = epsilon0*A/d
epsilon0 = 8.84*10^-12 F/m
Solve for the plate area A. You know C (the capacitance) and d (the plate spacing) already

(c) E = V/d newtons per coulomb. Get V from part (a)

d) = Q/A Get the area from (b)

Answer this Question

Related Questions

Physics - A parallel plate air capacitor of capacitance 245pF has a charge of ...
physics - An air-filled capacitor consists of two parallel plates, each with an ...
College Physics - A 12.0- A 12.0- A 12.0-V battery remains connected to a ...
Physics - Two circular metal disc each of 3.00 cm diamter are 1.5 mm apart make ...
physics - You have a parallel plate capacitor (with air between its plates) ...
Physics - Two plates, each of area 3.40*10-4 m2, are used to construct a ...
Physics - The electric field between the plates of a paper-separated capacitor ...
physics - The magnitude of the electric field between the plates of a parallel ...
Physics - Two parallel plate capacitors have circular plates. The magnitude of ...
physics - The magnitude of the electric field between two plates of a parallel ...

For Further Reading

First Name:
School Subject:
Answer: