if insulin has 6 cysteines, how many millimoles of IAA would be consumed in a blocking reaction containing 10 mmol of reduced insulin?
mass of cysteine - 121 g/mol.
To calculate the number of millimoles of IAA consumed in the blocking reaction, we need to determine the molar ratio between cysteine and IAA.
First, let's determine the molar mass of insulin by adding up the molar masses of its individual amino acids, including the six cysteines.
Insulin has a molar mass of approximately 5,800 g/mol.
Next, we need to find the molar ratio of cysteines to insulin. Insulin has a total of 6 cysteines, so the molar ratio of cysteines to insulin is 6:1.
Assuming that all cysteines react with IAA, we can calculate the number of millimoles of insulin by dividing the given mass of insulin (10 mmol) by the molar mass of insulin:
10 mmol / 5800 g/mol = 0.00172 moles of insulin
Now, let's calculate the number of millimoles of IAA using the molar ratio:
0.00172 moles of insulin × (6 moles of IAA / 1 mole of insulin) = 0.01032 moles of IAA
Finally, to convert moles to millimoles, we multiply the result by 1000:
0.01032 moles × 1000 = 10.32 millimoles of IAA
Therefore, in a blocking reaction containing 10 mmol of reduced insulin with 6 cysteines, approximately 10.32 millimoles of IAA would be consumed.