Posted by Jacob on Tuesday, January 29, 2008 at 10:45pm.
A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet

Algebra1  Anonymous, Tuesday, January 29, 2008 at 10:47pm
Did they leave at the same time?

Algebra1  Damon, Tuesday, January 29, 2008 at 10:58pm
They could not have left at the same time. Jacobyou left part of the problem out.
When you get it figured out, the distances are the same
d = rate * time
rate jet1 * time jet 1 = rate jet2 *(time jet 1  delay)

Algebra1  Jacob, Tuesday, January 29, 2008 at 10:58pm
no the second one left a half an hour later sorry i forgot to include that

Algebra1  Damon, Tuesday, January 29, 2008 at 11:01pm
then
564 *t = 744 * (t  .5)
solve for t, the time for jet 1
then if we want the time for jet 2, subtract 1/2 hour

Algebra1  Damon, Tuesday, January 29, 2008 at 11:17pm
Yes

Algebra1  Damon, Tuesday, January 29, 2008 at 11:22pm
But remember to subtract half hour for second plane

Algebra1  Angelica(:, Monday, October 10, 2011 at 7:11pm
564*2.07=744*2.07.5
564*2.07=744*1.57
1167.48=1168.08
how come it doesnt equal the same thing?
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