# Algebra1

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A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet

• Algebra1 - ,

Did they leave at the same time?

• Algebra1 - ,

They could not have left at the same time. Jacob-you left part of the problem out.
When you get it figured out, the distances are the same
d = rate * time
rate jet1 * time jet 1 = rate jet2 *(time jet 1 - delay)

• Algebra1 - ,

no the second one left a half an hour later sorry i forgot to include that

• Algebra1 - ,

then
564 *t = 744 * (t - .5)
solve for t, the time for jet 1
then if we want the time for jet 2, subtract 1/2 hour

• Algebra1 - ,

564t=744(t-.5)
564t=744t-372
564t-564t=744t-372-564t
0=180t-372
0+372=180t-372+372
372=180t
372/180=180t/180
2.07=t

Is that correct?

• Algebra1 - ,

Yes

• Algebra1 - ,

But remember to subtract half hour for second plane

• Algebra1 - ,

ok thank you for all of your help

• Algebra1 - ,

564*2.07=744*2.07-.5
564*2.07=744*1.57
1167.48=1168.08
how come it doesnt equal the same thing?