Posted by Jacob on .
A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet

Algebra1 
Anonymous,
Did they leave at the same time?

Algebra1 
Damon,
They could not have left at the same time. Jacobyou left part of the problem out.
When you get it figured out, the distances are the same
d = rate * time
rate jet1 * time jet 1 = rate jet2 *(time jet 1  delay) 
Algebra1 
Jacob,
no the second one left a half an hour later sorry i forgot to include that

Algebra1 
Damon,
then
564 *t = 744 * (t  .5)
solve for t, the time for jet 1
then if we want the time for jet 2, subtract 1/2 hour 
Algebra1 
Jacob,
564t=744(t.5)
564t=744t372
564t564t=744t372564t
0=180t372
0+372=180t372+372
372=180t
372/180=180t/180
2.07=t
Is that correct? 
Algebra1 
Damon,
Yes

Algebra1 
Damon,
But remember to subtract half hour for second plane

Algebra1 
Jacob,
ok thank you for all of your help

Algebra1 
Angelica(:,
564*2.07=744*2.07.5
564*2.07=744*1.57
1167.48=1168.08
how come it doesnt equal the same thing?