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Algebra1

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A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet

  • Algebra1 - ,

    Did they leave at the same time?

  • Algebra1 - ,

    They could not have left at the same time. Jacob-you left part of the problem out.
    When you get it figured out, the distances are the same
    d = rate * time
    rate jet1 * time jet 1 = rate jet2 *(time jet 1 - delay)

  • Algebra1 - ,

    no the second one left a half an hour later sorry i forgot to include that

  • Algebra1 - ,

    then
    564 *t = 744 * (t - .5)
    solve for t, the time for jet 1
    then if we want the time for jet 2, subtract 1/2 hour

  • Algebra1 - ,

    564t=744(t-.5)
    564t=744t-372
    564t-564t=744t-372-564t
    0=180t-372
    0+372=180t-372+372
    372=180t
    372/180=180t/180
    2.07=t

    Is that correct?

  • Algebra1 - ,

    Yes

  • Algebra1 - ,

    But remember to subtract half hour for second plane

  • Algebra1 - ,

    ok thank you for all of your help

  • Algebra1 - ,

    564*2.07=744*2.07-.5
    564*2.07=744*1.57
    1167.48=1168.08
    how come it doesnt equal the same thing?

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