Posted by **Jacob** on Tuesday, January 29, 2008 at 10:45pm.

A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet

- Algebra1 -
**Anonymous**, Tuesday, January 29, 2008 at 10:47pm
Did they leave at the same time?

- Algebra1 -
**Damon**, Tuesday, January 29, 2008 at 10:58pm
They could not have left at the same time. Jacob-you left part of the problem out.

When you get it figured out, the distances are the same

d = rate * time

rate jet1 * time jet 1 = rate jet2 *(time jet 1 - delay)

- Algebra1 -
**Jacob**, Tuesday, January 29, 2008 at 10:58pm
no the second one left a half an hour later sorry i forgot to include that

- Algebra1 -
**Damon**, Tuesday, January 29, 2008 at 11:01pm
then

564 *t = 744 * (t - .5)

solve for t, the time for jet 1

then if we want the time for jet 2, subtract 1/2 hour

- Algebra1 -
**Damon**, Tuesday, January 29, 2008 at 11:17pm
Yes

- Algebra1 -
**Damon**, Tuesday, January 29, 2008 at 11:22pm
But remember to subtract half hour for second plane

- Algebra1 -
**Angelica(:**, Monday, October 10, 2011 at 7:11pm
564*2.07=744*2.07-.5

564*2.07=744*1.57

1167.48=1168.08

how come it doesnt equal the same thing?

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