Posted by **Cassidy** on Monday, January 28, 2008 at 5:53pm.

Okay. How do I go about answering this question? And what is it really asking?

A watermelon has a mass of 118 kg. It is on a platform 5 m above the ground. When taken off the platform, it is allowed to slide down a ramp. How high above the ground is the watermelon at the moment its kinetic energy 4.61 kJ?

- Physics -
**Quidditch**, Monday, January 28, 2008 at 6:47pm
The initial potential energy of the watermelon is mass*acceleration*height or mgh for Earth. For practical purposes assume that total energy of the watermelon is constant. So the potential energy + the kinetic energy is constant. The kinetic energy is given at the point of interest. So the remaining potential energy is:

(118kg * g * 5m) - 4.61kj = ?

After you solve for the remaining potential energy, just use mgh again:

mgh = remaining potential energy

solve for h

- Physics -
**Quidditch**, Monday, January 28, 2008 at 6:51pm
Also, it is assumed there is no friction with the ramp.

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