posted by Matt on .
(x - 9/x) / (1 + x/3)
and (m^-1 + n^-1) / (m^-3 + n^-3)
I have no idea what to do
Answer to #2:
I subtracted the m's and subtracted the m's. It's one of the exponent rules.
I have NO idea how to do the first question.
you cant do that, Miley, the m's and n's are separated by an addition sign, so you cant use the quotient of powers rule
oh okay sry, at least i tried
for the first one, just multiply them using FOIL
x + (x^2)/3 - 9/x - 3
for the second, use the rule for negative exponents to write
(1/m + 1/n)/(1/m^3 + 1/n^3)
finding common denominators and simplifying both top and bottom I got
(m+n)/mn / (m^3 + n^3)/m^3n^3
= (m+n)/mn * (m^3n^3)/(m^3 + n^3)
= m^2n^2(m+n) / (m^3 + n^3)
the bottom factors to (m+n)(m^2 - mn + n^2)
so we have
m^2n^2(m+n) / ((m+n)(m^2 - mn + n^2))
= m^2n^2 / (m^2 - mn + n^2)