Posted by **ed** on Monday, January 28, 2008 at 6:54am.

a small ball of mass .85 kg is attached to one end of a 1 m long massless rod, and the other end of the rod is hung from a pivot. When the resulting pendulum is 25 degrees from the vertical, what is the magnitude of the torque about the pivot?

- AP physics -
**Christiaan**, Monday, January 28, 2008 at 7:09am
Torque is calculated by the formula:

t=r.F.sin(a) where a is the angle between the rod and the force acting on the rod(=25°),

r is the distance from the force to the pivot point(which is 1m),

and F is the gravity force acting on the ball(=m.g = 0.85kg.10m/s² =8.5 N)

So, the torque equals:

t=1m . 8,5N . sin(25°) = 3,59 Nm

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