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July 26, 2014

July 26, 2014

Posted by **matt** on Monday, January 28, 2008 at 6:38am.

- physics -
**Christiaan**, Monday, January 28, 2008 at 7:23amFirst we calculate the torque.

t=rxF=r.F.sin(b) where is the angle between r and F (which in this case equals 90°).

So in this case t= r.F = 0,15m.F = 0.075t + 0.045t²

We also know that I = 1.5 . 10^-3 kg.m²

and so we can calculate the angular acceleration (a) with the formula:

t = I.a

=> a = t/I = 50t + 30t²

Now, we need to find the angular velocity after 2 seconds. Since a=dw/dt (with w, the angular velocity), we can find the angular by taking the definite integral of a for t from 0 to 2

=> w = integral of 50t+30t² from 0 to 2=

(25.(2)²+10(2)^3)-(25.(0)²+10(0)^3)= 180-0 = 180

so the angular velocity after two seconds = 180 rad/s

- physics -
**ed**, Monday, January 28, 2008 at 7:24amthank you soooooooo much i really appreciate you taking your time to help

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