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Posted by **Cassidy** on Sunday, January 27, 2008 at 11:26pm.

mgh+1/2mvh=mgh+1/2mv^2+Fd

- Physics -
**drwls**, Sunday, January 27, 2008 at 11:57pmHow you use it depends upon the problem you are trying to solve.

It looks like you are trying to use conservation of energy to solve a problem of height and velocity of an object moving in a gravitational field, with a work or drag term (Fd) included. However the mvh on the left would have to be mv^2. Even more important, the v's and h's on the right and left sides shoule have different subscripts, since they would apply to different times along the trajectory.

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