I differ by a factor of 2
2[ A/(x+1) +B/(x-1) ]
A = -1/2, B = +1/2
2 int [ -.5 dx/(x+1) + .5 dx /(x-1) ]
1 int [ dx/(x+1) + dx/(x-1) ]
ln (x+1) + ln (x-1)
ln[ (x+1)/(x-1) ]
To see if your answer is correct, take the derivative. Itis
= [-(1/2)(x-1) + (1/2)(x+1)]/(x^2 -1)
Your riginal integrand is equal to 2/(x^2-1), so your answer seems to be off by a factor of 2.
Which I should have seen in the first place.
took ya long enuff
Yeah, but I am really old :)
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