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November 20, 2014

November 20, 2014

Posted by **Kristen** on Sunday, January 27, 2008 at 1:16pm.

Calculate the acceleration of the seed assuming that it does not slip?

Suppose that the turntable achieves its angular speed by starting from rest and undergoing a constant angular acceleration for .75 seconds. Calculate the minimum coefficient of static friction required for the seed not to slip during the acceleration period?

- AP Physics -
**Damon**, Sunday, January 27, 2008 at 2:23pmI do not know if it is 7.5 nautical miles or what, so I will call the distance from the center r.

convert 33 1/3 rev/mi to radians/s

w = 33 1/3 rev/min *1 min/60 s *2 pi rad/rev

= 3.49 rad/s

a = w^2 r = 12.2 r

in units of length you are using/s^2

since I do not know your length unit I must leave g as g instead of 9.8 m/s^2 or 32 ft/s^2 or whatever

mu = friction coef

Now we also have a tangential friction problem because the table is accelerating

tangential acceleration = r*(change in w/change in time)

= r * ( 3.49 rad/s /.75 s)

= r * 4.65 length units/s^2

total acceleration = sqrt(tangenial^2 + radial^2)

= r sqrt (4.65^2 + 12.2^2)

= r sqrt (170)

= 13.0 r

Now friction force = m a

m g mu = m (13 r)

mu = 13 r/g

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