Posted by Kristen on Sunday, January 27, 2008 at 1:16pm.
I do not know if it is 7.5 nautical miles or what, so I will call the distance from the center r.
convert 33 1/3 rev/mi to radians/s
w = 33 1/3 rev/min *1 min/60 s *2 pi rad/rev
= 3.49 rad/s
a = w^2 r = 12.2 r
in units of length you are using/s^2
since I do not know your length unit I must leave g as g instead of 9.8 m/s^2 or 32 ft/s^2 or whatever
mu = friction coef
Now we also have a tangential friction problem because the table is accelerating
tangential acceleration = r*(change in w/change in time)
= r * ( 3.49 rad/s /.75 s)
= r * 4.65 length units/s^2
total acceleration = sqrt(tangenial^2 + radial^2)
= r sqrt (4.65^2 + 12.2^2)
= r sqrt (170)
= 13.0 r
Now friction force = m a
m g mu = m (13 r)
mu = 13 r/g
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