What's the phase shift of "y = sin(3x - pi)"?
Is it pi/3 to the right?
yes it is
I agree. Relative to the curve y = sin 3x, and assuming you are plotting y vs x, sin(3x - pi)is shifted pi/3 to the right. In other words, when x is increased by pi/3, the argument (3x-pi)of the y = sin(3x - pi)function has the same value as 3x of the sin 3x function.
To determine the phase shift of the function y = sin(3x - π), we need to compare it to the standard form of the sine function: y = sin(x). The formula for phase shift in the sine function is given by:
Phase Shift = (c/b),
where c represents the horizontal shift and b represents the coefficient of x in the function.
In the given function, we have y = sin(3x - π). Comparing it to the standard form y = sin(x), we can observe that the coefficient of x in the given function is 3, which means b = 3. Additionally, the function is shifted horizontally by π units to the right, which corresponds to c = π.
So, using the formula for phase shift, we can calculate:
Phase Shift = (π/3).
Therefore, the correct phase shift of the function y = sin(3x - π) is π/3 to the right.