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posted by on .

Find the average value over the given interval.

y=3x^5; [-3,3]

I can't seem to get the answer, 0.
1/(3+3) [integral -3 to 3 (3x^5)dx]
and I get 273/2

  • Calculus - ,

    I took the antiderivative incorrectly. I figured out my mistake.

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