Homework Help: Calculus

Posted by Anonymous on Thursday, January 24, 2008 at 10:04pm.

Find the value or values of c that satisfy (f(b)-f(a))/(b-a) =f'(c)for the function f(x)=x^2+3x+3 on the interval [-2,1]. I can't seem to get -1/2, the answer given.

[((1)^2+3(1)+3)-((-2)^2+3(-2)+3)]/[1+2]
=2

Calculus - Anonymous, Thursday, January 24, 2008 at 11:06pm
I just set the 2= the derivative of the function (which is 2c+3) and solve for c. I just figured it out. No help needed here.

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