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March 29, 2017

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How much heat would be released by the condensation of 5.40 g of steam at 100 °C and the subsequent cooling of the water to 25 °C? [ÄHvap = 40.7 kJ/mol at 100 °C; Cp for H2O(l) is
4.18 J g-1 °C-1]

  • chemistry - ,

    Heat is released by condensation steam at 100 C to water at 100 C.
    q1 = mass x Hvap.

    q2 = heat is released by cooling water from 100 C to 25 C.
    q2 = mass x specific heat x (Tf - Ti)
    where Tf is final T and Ti is initial T.
    Both q1 and q2 are negative numbers.
    Total heat released is q1+q2.

  • chemistry - ,

    i did what u wrote above. but did not have the answer right. The answer from the book is 13.9 kJ

  • chemistry - ,

    Check your working. Note that dHvap is per MOLE and the answer q1 will be in

    kJ

    whereas the answer for q2 will be in

    J

    Please get back if you still get the wrong answer.

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