Posted by sonya on Thursday, January 24, 2008 at 6:32pm.
x^3-4x-2 [2,3]
the function is continuous between 2 and 3
at 2 f(2) = -2
at 3 f(3) = +13
The theorem states that for every number N between -2 and +13, there is some x between 2 and 3 such that f(x) = N
Now they did not give you an N so I will say 5 for example is between -2 and +13
The theorem says that some x between 2 and 3 will come out with f(x)= 5
I would have to solve it by trial and error but I know to start between 2 and 5
x f(x)
2 -2
try 2.5 --> 3.63 too small
try 2.7 --> 6.88 too big
try 2.6 --> 5.18 closer, a bit big
try 2.58 -> 4.85 a little small
try 2.585-> 4.93 well you get the idea
3 13
The theorem says that
Related Questions
math - i am wondering if the following answer to my math problem is correct f(x...
Use the intermediate value - Use the intermediate value theorem to show that the...
math - use intermediate value theorem to show f(x) has a zero f(x)= x^5 - 4x^4- ...
math - use intermediate value theorem to show f(x) has a zero f(x)= x^5 - 4x^4- ...
Use the intermediate value - Use the intermediate value theorem to show that the...
Algebra - For f(x) = x^3 – 4x – 7, use the Intermediate Value Theorem ...
Economic - 1) GDP does not include intermediate goods because a. that would ...
calculus - Use the intermediate value theorem to determine whether or not f(x)=x...
college algebra - Use the intermediate value theorem to determine whether the ...
College Algebra - 1. Use the Intermediate Value Theorem to show that the ...
For Further Reading
