4th grade Algebra
posted by Serena on .
How to solve this problem.
3XY=12

minus 3x to both sides
Y=123X. THEN DIVIDE BY 1 TO BOTH SIDES
SO Y=12+3X 
hard difficult immposible fail impassible

3XY=12
I think probably you are supposed to get +y alone on the left
first add 3x to both sides
3x + 3x  y = 3x + 12
or
y = 3x + 12
but we want +y, not  y
So multiply every term on both sides by 1
(1)(y) = (1)(3x) + (1)(12)
or
y = 3x  12 
y=4