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September 2, 2014

September 2, 2014

Posted by **Jessie** on Thursday, January 24, 2008 at 4:36pm.

y= (2x +1)^5(x^4 - 3)^6

- Calculus -
**Damon**, Thursday, January 24, 2008 at 4:54pmWell, why do them that way?

but

ln y = 5 ln (2x+1) + 6 ln (x^4-3)

(1/y)dy/dx = 5 (2/(2x+1)) + 6 (4 x^3/(x^4-3))

now multiply both sides by y which is still (2x +1)^5(x^4 - 3)^6

ps - I would have just done it as a product of functions of x

- Calculus -
**drwls**, Thursday, January 24, 2008 at 4:56pmlog y = 5 log (2x+1) + 6 log (x^4 -3)

(1/y)*dy/dx = 10/(2x +1) + 24 x^3/(x^4 -3)

dy/dx = (2x +1)^5(x^4 - 3)^6 *

[10/(2x +1) + 24 x^3/(x^4 -3)]

Check my work

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